p^4+40=p^2

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Solution for p^4+40=p^2 equation:


Simplifying
p4 + 40 = p2

Reorder the terms:
40 + p4 = p2

Solving
40 + p4 = p2

Solving for variable 'p'.

Reorder the terms:
40 + -1p2 + p4 = p2 + -1p2

Combine like terms: p2 + -1p2 = 0
40 + -1p2 + p4 = 0

Begin completing the square.

Move the constant term to the right:

Add '-40' to each side of the equation.
40 + -1p2 + -40 + p4 = 0 + -40

Reorder the terms:
40 + -40 + -1p2 + p4 = 0 + -40

Combine like terms: 40 + -40 = 0
0 + -1p2 + p4 = 0 + -40
-1p2 + p4 = 0 + -40

Combine like terms: 0 + -40 = -40
-1p2 + p4 = -40

The p term is -1p2.  Take half its coefficient (-0.5).
Square it (0.25) and add it to both sides.

Add '0.25' to each side of the equation.
-1p2 + 0.25 + p4 = -40 + 0.25

Reorder the terms:
0.25 + -1p2 + p4 = -40 + 0.25

Combine like terms: -40 + 0.25 = -39.75
0.25 + -1p2 + p4 = -39.75

Factor a perfect square on the left side:
(p2 + -0.5)(p2 + -0.5) = -39.75

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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